Speed Dates is no feeble full-motion video game – it’s a bold art film | Dominik Diamond

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For 4 points, that is (1/2)3=1/8(1/2)^3 = 1/8(1/2)3=1/8, the same 12.5% we measured earlier. There is one such event for each of the NNN points, so we have NNN events each with probability 1/2N−11/2^{N-1}1/2N−1.

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The result is almost what we need, but once more, the rules prohibit approximations that are exactly equal to r. The workaround is to subtract 1 from all sides of the inequality:

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