We're not going to tell you what happens in it, just that it exists, and you should watch it. Most of the Bridgerton cast members appear in it, and it's worth your time. Just don't let Netflix send you automatically to another show as the credits start rolling.
Adam Mastroianni
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Подростки распылили перцовый баллончик на пассажиров электрички под Петербургом20:54
A Riemannian metric on a smooth manifold \(M\) is a family of inner products \[g_p : T_pM \times T_pM \;\longrightarrow\; \mathbb{R}, \qquad p \in M,\] varying smoothly in \(p\), such that each \(g_p\) is symmetric and positive-definite. In local coordinates the metric is completely determined by its values on basis tangent vectors: \[g_{ij}(p) \;:=\; g_p\!\left(\frac{\partial}{\partial x^i}\bigg|_p,\; \frac{\partial}{\partial x^j}\bigg|_p\right), \qquad g_{ij} = g_{ji},\] with the matrix \((g_{ij}(p))\) positive-definite at every point. The length of a tangent vector \(v = \sum_i v^i \frac{\partial}{\partial x^i}\in T_pM\) is then \(\|v\|_g = \sqrt{\sum_{i,j} g_{ij}(p)\, v^i v^j}\).
На Ближнем Востоке исчерпали мощности по хранению нефтиBloomberg: В Саудовской Аравии исчерпали мощности по хранению нефти